9^x-(28/3)(3^x)+3=0

Solution for 9^x-(28/3)(3^x)+3=0 equation:

9^x-(28/3)(3^x)+3=0


Domain of the equation: 3)3^x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

9^x-(+28/3)3^x+3=0

We multiply all the terms by the denominator


9^x*3)3^x-(+3*3)3^x+28=0

We add all the numbers together, and all the variables

9^x*3)3^x-93^x+28=0

Wy multiply elements

27x^2=0

a = 27; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·27·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{54}=0$